Respuesta :

ijeggs

Answer:

Option E

Explanation:

The statement int z=50/10.00;  will not compile as the compiler will say "Incompatible types" or "type mismatch". The reason for this is because the expression will evaluate to 5.0 which is a floating point value and cannot be stored in an integer value for which it was initially declared. To avoid this error, the variable z, may be re-declared as a double. double z=50/10.00;

stigawithfun

Answer:

(e) none of the above, a run-time error arises because z is an int and 50/10.00 is not.

Explanation:

Given;

int z = 50/10.00

The result of the right hand side of the code (50/10.00) will give 5.00 which is a floating point number and definitely not an integer. Therefore, assigning such to a variable z of type int will raise an error.

Two ways to fix this is;

i. by type casting the result from the right hand side to an integer,

ii. changing the type of variable z to a float or a double.

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