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Ann wants to organize her sculptures on some of the shelves in her room. She puts 15 sculptures per shelf, one shelf has only 14 on it. if she puts 12 sculptures per shelf, one shelf has only 11 sculptures on it. what is the least number of sculptures that Ann could have?

Respuesta :

Answer:

The answer to the question is

The least number of sculptures that Ann could have = 119 sculptures

Step-by-step explanation:

Number of sculptures = 15x + 14 = 12y +11

where y > x, but

hence 15x =12y -3, dividing by 3 we have

5x = 4y - 1 or 4y = 5x + 1 therefore the value of 4y must be two digit number ending in 6.

Investigating from the digits we find the first suitable two digit numbers

16, 26, 36, 46

of the above numbers, only 36 is a factor of 4 hence

solving for y and x with 4y = 36 we have y = 9 and x = (36-1)/5 = 7

y = 9, and x = 7  

Hence Ann has  15×7 + 14 sculptures or 119 sculptures

Answer:

59

Step-by-step explanation:

LCM (12,15) = 60

x+1=60, so x=59

I PROMISE THIS IS RIGHT, it worked for my computer.

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