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A rectangular sharp-crested weir is contracted on both sides, and the opening is 1.2 m wide. At what height (Hw) should it be placed within a channel to maintain an upstream depth of 2.5 m for a flow of 0.5 m3/s

Respuesta :

Answer:

H_w = 2.129 m

Explanation:

given,

Width of the weir, B = 1.2 m

Depth of the upstream weir, y = 2.5 m

Discharge, Q = 0.5 m³/s

Weir coefficient, C_w = 1.84 m

Now, calculating the water head over the weir

[tex]Q = C_w BH^{3/2}[/tex]

[tex]H = (\dfrac{Q}{C_wB})^{2/3}[/tex]

[tex]H = (\dfrac{0.5}{1.84\times 1.2})^{2/3}[/tex]

[tex]H = 0.371\ m[/tex]

now, level of weir on the channel

H_w = y - H

H_w = 2.5 - 0.371

H_w = 2.129 m

Height at which weir should place is equal to 2.129 m.

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