Respuesta :
Answer:
3.1 more charges flow across the plates when mylar is used instead of vacuum space/air.
Explanation:
From Q = CV, the charge, Q is directly proportional to capacitance, C, and, for the capacitance of a parallel plate capacitor, it is given as: C = ε(A/d)
where ε represents the absolute permittivity of the dielectric material
This means that the capacitance is directly proportional to the absolute permittivity of the dielectric material.
Q = CV = (ε(A/d)) V = εAV/d
This means that, provided the other parameters (area of conductive plate, potential difference between the plates, distance between the plates) are constant, the charges are directly proportional to the absolute permittivity of the dielectric material.
Q ∝ε
Relative permittivity of Mylar = 3.1 (obtained from literature)
The relative permittivity of a material is its (absolute) permittivity expressed as a ratio relative to the vacuum permittivity.
Q(vacuum space/air) ∝ε(vacuum space/air)
Q(mylar) ∝ε(mylar)
ε(mylar) = 3.1 ε(vacuum space/air)
Therefore,
Q(mylar) ∝3.1ε(vacuum space/air)
Therefore, 3.1 more charges flow across the plates when mylar is used instead of vacuum space/air.
Hope this helps!!
