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if there are 500 people in a population, and 150 are homozygous HbA/hba, 150 are homozygous hbs/hbs, and 200 are heterozygous hba/hbs, what is the frequency of the hba allele in that population

Respuesta :

Answer:

[tex]0.547[/tex]

Explanation:

Given -

Total Population - [tex]500[/tex]

Individuals with homozygous HbA/hbA genotype - [tex]150[/tex]

Individuals with homozygous hbs/hbs genotype -[tex]150[/tex]

Individuals with heterozygous hba/hbs genotype -  [tex]200[/tex]

Let us assume the given population is in Hardy Weinberg' equilibrium

The frequency of individuals in the given population with homozygous HbA/hba genotype is equal to number of individuals with homozygous HbA/hba genotype divided by total population.

[tex]\frac{150}{500} \\= 0.3[/tex]

The frequency of hba allele is equal to

[tex]\sqrt{0.3} \\= 0.5477[/tex]

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