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If the 3.90 m solution from Part A boils at 103.45 âC, what is the actual value of the van't Hoff factor, i? The boiling point of pure water is 100.00 âC and Kb is equal to 0.512 âC/m. Express your answer numerically.

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Answer:

Van't Hoff factor is 1.72 ≅ 2

Explanation:

Let's apply the colligative property of boiling point elevation:

ΔT = Kb . m . i

ΔT = Boiling T° of solution - T° boiling of pure solvent

103.45 °C - 100°C = 0.512 °C/m . 3.90 m . i

3.45 °C /  0.512 m/°C . 3.90 m = i

1.72 = i  ≅ 2

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