A woman at an airport is towing her 16.0-kg suitcase at constant speed by pulling on a strap at an angle θ above the horizontal. She pulls on the strap with a 39.5-N force, and the friction force on the suitcase is 20.0 N. Use g=9.8 m/s2.a) Draw a free-body diagram of the suitcase
(b) What angle does the strap make with the horizontal?
(c) What normal force does the ground exert on the suitcase?
Answer:
Angle does the strap make with the horizontal is [tex]59.58 ^0[/tex]
normal force does the ground exert on the suitcase is 136.8 N
Explanation:
1)Freebody diagram show in the figure(see the atachment)
2) Take horizontal forces from the free body diagram
[tex]f=Fcos\theta\\cos\theta=\frac{20}{39.5}\\cos\theta=0.50\\\theta=cos^{-}(0.506)\\\theta=59.58^0[/tex]
3) take vertical components of forces, we get normal force
[tex]mg=N+Fsin\theta\\N=mg-F\thetsin\theta\\N=16\times 9.8-39.5 \times cos 59.58\\N=136.8 N[/tex]
