Answer:
200 nm is the thinnest film that produces a strong reflection for green light with a wavelength of 500 nm
Explanation:
If two reflected waves interfere constructively ,strong reflection is produced. Two reflected waves will experience a phase change
For constructive interference
[tex]2\times n\times t=m\lambda[/tex]
for thinnest film m=1
refractive index should be taken for film n=1.25
thickness of the thinnest film is
[tex]t=\frac{m\lambda}{2n} \\t=\frac{1\times 500}{2\times 1.25} \\t=200 nm[/tex]
"200 nm" will be the thinnest film.
Given:
Greenlight wavelength,
Thinnest film,
Refractive index,
For constructive interference,
→ [tex]2\times n\times t=m \lambda[/tex]
→ [tex]t = \frac{m \lambda}{2n}[/tex]
→ [tex]= \frac{1\times 500}{2\times 1.25}[/tex]
→ [tex]= 200 \ nm[/tex]
Thus the correct answer is "200 nm".
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