Answer:
The answer to this is
the new pressure will be the same as the old pressure
P₁ = P₂ the pressure will not change
Explanation:
The known variables are as follows
V₁ = initial volume
V₂ = final volume
T₁ = initial temperature
T₂ = final temperature
P₁ = initial pressure and
P₂ = final pressure
The combined as equation is [tex]\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }[/tex]
if the absolute temperature and volume of the container are both halved, then
V₂ = V₁/2 and T₂ = T₁/2, thus we have
[tex]\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} \frac{V_{1} }{2} }{\frac{T_{1} }{2} }[/tex] from where we have, by canceling like terms on both sides
P₁ V₁/T₁ = P₂ V₁/T₁
or P₁ = P₂ The pressure remains the same
