Answer:
[tex]w=4.88*10^{-3}m\\or\\w=4.88mm[/tex]
Explanation:
Given data
Diameter D=0.50 mm
Wavelength λ=500 nm
Length L=2.0 m
To find
Width w
Solution
Circular aperture of diameter D will have bright central maximum of diameter:
w=(2.44λL)/D
[tex]w=(\frac{2.44(500*10^{-9}m )(2.0m)}{0.50*10^{-3}m} )\\w=4.88*10^{-3}m\\or\\w=4.88mm[/tex]
