Answer:
43°
Explanation:
Sin tita m= mlambda/d
Sin 20°= lambda/d
Sin tita 2= 2(lambda/d)
Sin tita 2= 2 sin 20
Sin tita 2= 0. 684
Tita 2= sin-1(0. 684)
Tita 2= 43°
Thus, the angle of the second order maximum is 43°
Answer:
43.2°
Explanation:
Using the formula showing the condition necessary to obtain interference (constructive) for a diffraction grating which is;
d sin Θ = m x λ
where;
d = distance between slits in the grating.
Θ = angle of travel relative to the incident direction.
λ = wavelength of the light.
m = order of the maximum.
Making sin Θ subject of the formula, we have;
sin Θ = ( m x λ ) / d ---------------------(i)
For the first-order maximum, m = 1; and Θ = 20.0°
Substituting m and Θ into the equation (i) above, we have
=> sin 20.0° = λ / d
=> 0.3420 = λ / d
Therefore to get the angle of the second order maximum, substitute m = 2 and λ / d = 0.3420 into the equation (i) above
sin Θ = ( 2 x 0.3420)
sin Θ = 0.6840
Θ = (0.6840)
Θ = 43.157
Θ = 43.2°
