Answer:
Explanation:
Given
Length of wire is L
Area of cross-section is A
Resistance of wire is given by
[tex]R=\frac{\rho L}{A}[/tex]
where [tex]\rho =resistivity[/tex]
if wire is cut into two halves of equal length then
[tex]L'=0.5 L[/tex]
New resistance of each piece
[tex]R'=\frac{\rho \cdot 0.5L}{A}[/tex]
[tex]R'=0.5 R[/tex]
if they are connected in parallel then net resistance is given by
[tex]R'_{parallel}=\frac{R'\times R'}{R'+R'}[/tex]
[tex]R'_{parallel}=\frac{R'}{2}[/tex]
[tex]R'_{parallel}=\frac{R}{4}[/tex]
Thus Net resistance of new connection is [tex]\frac{1}{4}[/tex] th of the previous one