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The wings of some beetles have closely spaced parallel lines of melanin, causing the wing to act as a reflection grating. Suppose sunlight shines straight onto a beetle wing. If the melanin lines on the wing are spaced 2.0 µm apart, what is the first-order diffraction angle for green light (λ = 550 nm)?

Respuesta :

Answer:

[tex]16[/tex] degrees

Explanation:

As we know -

[tex]d sin \theta = m\lambda\\[/tex]

m is the order of the minima to the central axis

d is the width of the slit

[tex]\lambda[/tex] is the wavelength of the light

and

[tex]\theta[/tex] is the diffraction angle

Given

[tex]\lambda = 550\\d = 2.0[/tex] micrometer

Substituting the given values in above equation, we get -

[tex]\theta = sin^{-1} (\frac{\lambda}{d})\\\theta = sin^{-1} (\frac{550*10^{-9}}{2 * 10^{-6}})\\\theta = 15.96[/tex]degree

Approximately [tex]16[/tex] degrees

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