Respuesta :
Answer:
a) [tex]\frac{27}{64}[/tex]
b)[tex]\frac{1}{32}[/tex]
c) [tex]\frac{27}{64}[/tex]
d) [tex]\frac{3}{64}[/tex]
Explanation:
The correct question is
Organisms with the genotypes AABbCcDd and AaBbCcDd are crossed. What are the expected proportions of the following progeny?
a. A_B_C_D_
b. AabbCcDd
c. a phenotype identical to either parent
d. A_B_ccdd
Solution
In such question the probability for each allele pair is to be determines separately
For instance,
AA * Aa will produce AA, Aa, AA, Aa this means that all the the probability of getting both AA and Aa is [tex]\frac{1}{2}[/tex]
Like wise when Bb and Bb are crossed, BB, Bb, Bb, and bb are produced. So the probability of getting dominant trait i.e BB or Bb is [tex]\frac{3}{4}[/tex] and recessive trait i.e bb is [tex]\frac{1}{4}[/tex]
Chance to get homozygous bb only or BB only is [tex]\frac{1}{4}[/tex]
and chance of getting Bb is [tex]\frac{1}{2}[/tex]
Like Bb and Bb cross, the same will be the probabilities for Cc and Cc cross and Dd and Dd cross
Part A)
[tex]\frac{1}{4} * \frac{3}{4} * \frac{3}{4} * \frac{3}{4} \\= \frac{27}{64}[/tex]
Part B)
[tex]\frac{1}{4} * \frac{1}{2} * \frac{1}{2}* \frac{1}{2}\\= \frac{1}{32}[/tex]
Part C)
[tex]\frac{1}{4} * \frac{3}{4} * \frac{3}{4} * \frac{3}{4} \\= \frac{27}{64}[/tex]
Part D)
[tex]\frac{3}{4} * \frac{1}{4} * \frac{1}{4} * \frac{1}{4} \\= \frac{3}{64}[/tex]
