Answer:
We are not told what to calculate, but the following are possible:
1. Margin of error (E) = 9.30 (approx.)
2. Confidence interval (CI) = [220.70 < μ < 239.30] - Approx.
Step-by-step explanation:
We are not told what to calculate, but the following are possible:
1. Margin of error (E), and
2. Confidence interval (CI)
Given that:
Sample size (n) = 10
Mean (x bar) = 230 and,
Standard deviation (sd) = 15.
We assumed, 95% confidence level.
And is approximately normal. This implies that, we should use Z statistics instead of t statistics.
1) E = ±Z * [tex]\frac{\sigma}{\sqrt{n} }[/tex]
E = ±1.96 * 4.743416 = 9.297095
E = 9.30 (approx.)
2) CI = xbar ± E
CI = 230 ± 9.297095
CI = 220.7029 < μ < 239.2971
CI = [220.70 < μ < 239.30] - Approx.
