Answer:
[tex]0.148[/tex]
W/m2
Explanation:
As we know the intensity of transmitted light can be determined by equation given below -
[tex]I = I_0cos^2\alpha[/tex]
where I is the intensity of transmitted light
is equal to the angle of the polarization of input light
[tex]I_0[/tex] is the intensity of input light.
Given -
Intensity of input light [tex]I_0[/tex] [tex]= 0.45[/tex]
W per square meter
[tex]\alpha = 55[/tex] degrees
Substituting the given values in above equation, we get -
[tex]I = 0.45 * cos^2 (55)\\= 0.148[/tex]
