Answer:Angular width of the electromagnetic wave after it emerges from between the buildings is 2.761 degree
Explanation:
The wavelength of the electromagnetic wave is
[tex]\lambda=\frac{c}{f} \\\lambda=\frac{3\times 10^8}{830\times 10^6} \\\lambda=0.361 m[/tex]
Consider two buildings as a single slit, for single slit diffraction dark fringes are located an angle of
[tex]\theta _{p}=sin^{-1}\frac{\lambda}{a}[/tex]
where [tex]\lambda[/tex] is frequency, [tex]a[/tex] is space between buildings.
For the first dark fringes
[tex]\theta _{1}=sin^{-1}\frac{\lambda}{a}\\\theta _{1}=sin^{-1}\frac{0.3614}{15}\\\theta _{1}=1.38^{0}[/tex]
Angular width of the electromagnetic wave after it emerges from between the buildings is
[tex]\Delta\theta =2\theta _{1}\\\Delta\theta =2\times 1.38\\\Delta\theta =2.761^0[/tex]
