Answer:
[tex]\dfrac{1}{15}[/tex]
Step-by-step explanation:
A 8-sided die is rolled twice and at least one 3 was rolled. So, the total possible outcomes are
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(3,7),(3,8),(1,3),(2,3),(4,3),(5,3),(6,3),(7,3),(8,3)
If the same number comes up both times we say that "doubles" was rolled.
Total favorable outcomes = {3,3}
Total number of favorable outcomes = 1
We need to find the probability that doubles was roll.
[tex]Probability=\dfrac{\tex{Favorable outcomes }}{\text{Total outcomes}}[/tex]
[tex]Probability=\dfrac{1}{15}[/tex]
Therefore, the probability that doubles was roll is [tex]\dfrac{1}{15}[/tex].
