Answer: The screen should be located 7 m from the lens.
Step-by-step explanation:
As per given , we have
Focal length : f = 156.00 mm
Object distance : u = -159.57 mm
To find : Image distance (v)
Using lens formula : [tex]\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}[/tex]
[tex]\Rightarrow\ \dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}[/tex]
Substitute all corresponding values , we get
[tex]\dfrac{1}{v}=\dfrac{1}{156}+\dfrac{1}{-159.57}\\\\=\dfrac{1}{156}-\dfrac{1}{159.57}\\\\=\dfrac{1}{156}-\dfrac{100}{15957}\\\\=\dfrac{119}{829764}\\\\ v=\dfrac{829764}{119}\approx6972.81\ mm[/tex]
Since 1 m = 1000 mm
So, v≈ 7.0 m
Hence, the screen should be located 7 m from the lens.
