contestada

Fill in the empty function so that it returns the sum of all the divisors of a number, without including it. A divisor is a number that divides into another without a remainder.

Respuesta :

MrRoyal

Answer:

// Program is written in C++

// Comments are used to explain some lines

// Only the required function is written. The main method is excluded.

#include<bits/stdc++.h>

#include<iostream>

using namespace std;

int divSum(int num)

{

// The next line declares the final result of summation of divisors. The variable declared is also

//initialised to 0

int result = 0;

// find all numbers which divide 'num'

for (int i=2; i<=(num/2); i++)

{

// if 'i' is divisor of 'num'

if (num%i==0)

{

if (i==(num/i))

result += i; //add divisor to result

else

result += (i + num/i); //add divisor to result

}

}

cout<<result+1;

}

lhmarianateixeira

In this exercise, using the knowledge of computational language in C++, we have that this code will be written as:

The code is in the attached image.

We can write the C++  as:

#include<bits/stdc++.h>

#include<iostream>

using namespace std;

int divSum(int num)

{

int result = 0;

for (int i=2; i<=(num/2); i++)

{

if (num%i==0)

{

if (i==(num/i))

result += i; //add divisor to result

else

result += (i + num/i); //add divisor to result

}

}

cout<<result+1;

}

See more about C++ at brainly.com/question/19705654

Ver imagen lhmarianateixeira