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A large tower is to be supported by a series of steel wires. It is estimated that the load on each wire will be 10,100 N. Determine the minimum required wire diameter assuming a factor of safety of 1.5 and a yield strength of 900 MPa.

Respuesta :

Answer:

d=4.63 mm

Explanation:

Given that

Load ,P = 10,100 N

FOS = 1.5

Sy= 900 MPa

Therefore the working stress will be

[tex]S=\dfrac{900}{1.5}=600\ MPa[/tex]

Lets take the diameter of wire = d mm

The area[tex] A=\dfrac{\pi}{4}d^2[/tex]

For design purpose

[tex]\sigma=\dfrac{P}{A}[/tex]

[tex]S=\dfrac{P}{A}[/tex]

[tex]A=\dfrac{P}{S}[/tex]

[tex]A=\dfrac{10100}{600}\ mm^2[/tex]

A=16.83 mm²

[tex]16.83=\dfrac{\pi}{4}d^2[/tex]

[tex]d^2=21.44\ mm^2[/tex]

d=4.63 mm

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