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A manager has a list of items that have been sorted according to an item ID. Some of them are duplicates. She wants to add a code to the database that assigns a 1 to the item if it is​ unique, and if there are​ duplicates, assigns the number of the duplicate. An example is shown below. The first two items are​ unique, so the repeat code is 1.​ However, Item ID 37699 is listed six​ times, so the codes are assigned from 1 to​ 6, and so on. Explain how to assign the correct code using an IF statement.

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Answer:

The solution code is written in Python:

  1. items = [{"id": 37697, "code": ""},{"id": 37698, "code": ""},{"id": 37699, "code": ""},{"id": 37699, "code": ""}, {"id": 37699, "code": ""},
  2. {"id": 37699, "code": ""},{"id": 37699, "code": ""},{"id": 37699, "code": ""},{"id": 37700, "code": ""} ]
  4. items[0]["code"] = 1
  6. for i in range(1, len(items)):
  7.    if(items[i]["id"] == items[i-1]["id"]):
  8.        items[i]["code"] = items[i-1]["code"] + 1
  9.    else:
  10.        items[i]["code"] = 1
  12. print(items)

Explanation:

Firstly, let's create a list of dictionary objects. Each object holds an id and a code (Line 1-2). Please note all the code is initialized with zero at the first beginning.

Next, we can assign 1 to the code property of items[0] (Line 4).

Next, we traverse through the items list started from the second element (Line 6). We set an if condition to check if the current item's id is equal to the previous item (Line 7). If so, we assign the previous item's code + 1 to the current item's code (Line 8). If not, we assign 1 to the current item's code (Line 10).

At last, we print out the item (Line 12) and we shall get

[{'id': 37697, 'code': 1}, {'id': 37698, 'code': 1}, {'id': 37699, 'code': 1}, {'id': 37699, 'code': 2}, {'id': 37699, 'code': 3}, {'id': 37699, 'code': 4}, {'id': 37699, 'code': 5}, {'id': 37699, 'code': 6}, {'id': 37700, 'code': 1}]