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A pipe contains water at 500,000 Pa above atmospheric pressure. If you patch a 4.00 mm diameter hole in the pipe with a piece of bubble gum, how much force must the gum be able to withstand?

Respuesta :

abidemiokin

Answer: 6.284N

Explanation:

Pressure is the ratio of force exerted to cross sectional area of the material.

Pressure = Force/Area

Pressure = 500,000Pa

Area = Πd²/4 where d is the diameter of the hole.

If d = 4mm = 0.004m

Area = Π×0.004²/4

Area = 1.26×10^-5m²

Force = Pressure×Area

Force = 500,000× 1.26×10^-5

F = 6.284N

The gum must be able to withstand 6.284N force

Cricetus

The force must the gum be able to withstand will be "6.284 N".

According to the question:

  • Pressure = 500,000 Pa
  • Diameter = 4.00 mm or, 0.004 m

We know that,

→ [tex]Area = \frac{\sqcap d^2}{4}[/tex]

By putting the values,

           [tex]= \frac{\sqcap (0.004)^2}{4}[/tex]

           [tex]= 1.26\times 10^{-5} \ m^2[/tex]

hence,

The force will be:

= [tex]Pressure\times Area[/tex]

= [tex]500000\times 1.26\times 10^{-5}[/tex]

= [tex]6.284 \ N[/tex]

Thus the answer above is correct.

Learn more about pressure here:

https://brainly.com/question/13128337

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