Suppose you are on a ship at rest in the ocean, observing the crests of a passing sinusoidal wave. You estimate that the crests are 75 m apart.

1. Approximately how much time elapses between one crest reaching your ship and the next?
A. 3 s
B. 5 s
C. 7 s
D. 12 s

2. The captain starts the engines and sails directly opposite the motion of the waves at 4.5 m/s. Now how much time elapses between one crest reaching your ship and the next?
A. 3 s
B. 5 s
C. 7 s
D. 12 s

3. In the deep ocean, a longer-wavelength wave travels faster than a shorter-wavelength wave. Thus, a higher-frequency wave travels ____ a lower-frequency wave.
A. Faster than
B. At the same speed as
C. Slower than

Respuesta :

1) Time taken: 17.4 s

2) Time taken: 8.5 s

3) A higher-frequency wave travels C) slower than a lower-frequency wave

Explanation:

1)

The speed of deep-water waves is given by the equation

[tex]v=\sqrt{\frac{g\lambda}{2\pi}}[/tex]

where

[tex]g=9.8 m/s^2[/tex] is the acceleration due to gravity

[tex]\lambda[/tex] is the wavelength of the wave

For the wave in the problem, the distance between the crests is 75 m, so this is also the wavelength of the wave:

[tex]\lambda=75 m[/tex]

Therefore, the speed of the wave is:

[tex]v=\sqrt{\frac{(9.8)(75)}{2\pi}}=4.3 m/s[/tex]

Now we can calculate the time elapsed between one crest and the next: in fact, the distance that the wave has to cover is

d = 75 m

Therefore, time taken is

[tex]t=\frac{d}{t}=\frac{75}{4.3}=17.4 s[/tex]

2)

In  this case, the captain starts the engines and his boat moves in the opposite direction at a velocity of

[tex]v_b = -4.5 m/s[/tex]

As a consequence, this means that the relative velocity of the crests of the wave relative to the boat will be

[tex]v'=v-v_b = 4.3-(-4.5)=8.8 m/s[/tex]

Again, the distance between one crest and the next one is

[tex]d=75 m[/tex]

Therefore, the time that elapses between one crest and the next one will be:

[tex]t=\frac{d}{v'}=\frac{75}{8.8}=8.5 s[/tex]

3)

The relationship between speed, frequency and wavelength for any wave is given by the wave equation:

[tex]v=f \lambda[/tex]

where

v is the speed

f is the frequency

[tex]\lambda[/tex] is the wavelength

The equation can be rewritten as

[tex]f=\frac{v}{\lambda}[/tex]

In this problem, we are told that longer-wavelength wave travels faster than a shorter-wavelength wave. From the equation above, we see that the frequency of a wave is inversely proportional to the wavelength: therefore, a longer-wavelength wave has lower frequency, and a shorter-wavelength wave has higher frequency. This means that a high-frequency wave travels slower than a lower frequency wave, so the correct option is

C. Slower than

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