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A man claims that he can hold onto a 11.0-kg child in a head-on collision as long as he has his seat belt on. Consider this man in a collision in which he is in one of two identical cars each traveling toward the other at 55.0 mi/h relative to the ground. The car in which he rides is brought to rest in 0.05 s.Find the magnitude of the average force needed to hold onto the child.

Respuesta :

Answer:

5412 N

Explanation:

Let's convert the velocity to metres per second. 55 miles per hour is equivalent to 24.6 metres per second.

Before the collision, the child had a momentum of [tex]mv=11 \times 24.6[/tex] where m = mass of child and v = velocity of child.

After the collision, he is brought to rest. Hence, the final momentum is 0 since the final velocity is 0.

By Newton's second law, the impulse = change in momentum. Impulse is the product of the average force and the time for which it acts.

[tex]I = Ft =mv-mu[/tex]

[tex]F\times0.05 =0-11 \times 24.6[/tex]

[tex]\F = dfrac{11 \times 24.6}{0.05}= 5412[/tex] N