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The compound AX2 decomposes according to the equation, 2 AX2(g) => 2 AX(g) + X2(g). In one experiment, AX2 was measured at various times, and these data recorded: Time (s) {AX2} mol/L 0 0.0500 2.0 0.0448 6.0 0.0300 8.0 0.0249 10.0 0.0209 20.0 0.0088 What is the average rate from 2.0 to 6.0 seconds in mol / L s? Use 4 decimal places

Respuesta :

Answer:

Explanation:

[ AX₂] is decomposing to form products .

Rate of reaction =1/2 x- [ AX₂] / t

rate between 0 to 2 s

- [ AX₂] = change in concentration of   AX₂ = .05 - .0448

= .0052 mol/L ,

time t = 2s

1/2 x [- AX₂] / t  = 1/2 x .0052 / 2

= .0013 mol/L.s

between 2 to 6 second

- [ AX₂]  = .0448 - .0300

=.0148 mol/L

t = 6-2 = 4 s

1/2 x [ -AX₂] / t  = 1/2 x .0148 / 4

= .00185 mol/L.s

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