Answer:
V = 141.64 L
Explanation:
Data Given:
No. of Particles = 3.81 × 10²⁴ Molecules
M.Mass of SO₂ = 64.066 g/mol
Standard Pressure = 1 atm
Standard Temperature = 273.15 K
Gas constant = 0.08205 L.atm.K⁻¹.mol⁻¹
Volume = ??
Step 1: Calculate Moles of SO₂ as;
We know that one mole is equal to 6.022 × 10²³ particles. It means,
6.022 × 10²³ molecules are contained in = 1 mole of SO₂
So,
3.81 × 10²⁴ molecules will be in = X moles of SO₂
Solving for X,
X = 3.81 × 10²⁴ molecules × 1 mol / 6.022 × 10²³ molecules
X = 6.32 moles
Step 2: Calculate Volume as;
Assuming that the gas is acting ideally we will apply ideal gas equation.
P V = n R T
Solving for V,
V = n R T / P
Putting values,
V = (6.32 mol × 0.08205 L.atm.K⁻¹.mol⁻¹ × 273.15 K) / (1 atm)
V = 141.64 L
