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Suppose a basketball team had a season of games with the following characteristics: ⢠Of all the games, 56% were at-home games. Denote this by H (the remaining were away games). ⢠Of all the games, 25% were wins. Denote this by W (the remaining were losses). ⢠Of the at-home games, 36% of games were wins. Of all the games, % of games were at-home wins. (Please round your answer to one decimal place.)

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Answer:

20.2%

Step-by-step explanation:

Let the total number of games be [tex]g[/tex].

At-home games, H = 56% of [tex]g[/tex] = [tex]\dfrac{56}{100}\times g= 0.56g[/tex]

Wins at home = 36% of H

= 36% of [tex]0.56g[/tex] =[tex]0.36\times0.56g=0.2016g[/tex]

To convert to percentage, multiply by 100%.

[tex]0.2016\times100\%=20.16\%=20.2\%[/tex] to 1 decimal place.

The percentage of games should be at home wins should be 20.2%

Calculation of percentage:

Here we assume the number of games be x

So at home it should be 0.56g

Now

Wins at home should be = 36% of x = [tex]= 36\% \times 0.56x[/tex] = 0.2016g

Now

In percentage form it should be 20.2%

Learn more about the percentage here: https://brainly.com/question/13919511

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