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A football is thrown at an initial velocity of 51 mph at an angle of 37 degrees. How many yards is the football thrown

Respuesta :

Chelboy

Answer:250.03m

Explanation:

Initial velocity =u=51mph

Angle=β=37

Acceleration due to gravity=g=10

The distance covered by the football is the range

Range=(u^2xsin2β)/g

Range=(51^2xsin(2x37))/10

Range=(51x51xsin74)/10

Range=(2601xsin74)/10

Range=(2601x0.9613)/10

Range=(2500.3)/10

Range=250.03m

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