Step-by-step explanation:
[tex] \because \angle \: XQL = \angle \:MQR \: \\ (vertically \: opposite \: angles) \\ \therefore \: - 5b + 82 = - 3b + 74 \\ \therefore \: - 5b + 3b = 74 - 82\\ \therefore \: - 2b = - 8\\ \therefore \: b = \frac{ - 8}{ - 2} \\ \therefore \: b = 4 \\ \\ m\angle \: XQL = - 5b + 82 \\ = - 5 \times 4 + 82 \\ = - 20 + 82 \\ = 62 \degree \\ \huge \pink{ \boxed{ \therefore \: m\angle \: XQL = 62 \degree }}[/tex]
