The graph of y=tan(x) is vertically stretched by a factor of 2, shifted a distance of 1 units to the left, and then translated 7 units upward.
Write the equation for the curve in its final position.

f(x)=

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Answer:

Equation for the curve in its final position is y = 2tan( x + 1 ) + 7.

Step-by-step explanation:

We have to find equation for the curve of y=tan(x) ,with following transformations:

vertically stretched by a factor of 2:  y = 2tan(x)

shifted a distance of 1 units to the left: y = 2tan( x+1 )

translated 7 units upward: y = 2tan( x + 1 ) + 7

The equation for the curve in its final position is y = 2tan(x+2) + 7

Given the function f(x), if the function is stretched by a factor of "k", the resulting function will be kf(x)

If shifted a distance of "a" units to the left, and then translated b units upward, the resulting expression will be kf(x + a) + b

Given the function y = tan(x) if the function is vertically stretched by a factor of 2, the resulting function will be y = 2tan(x)

If shifted a distance of 2 units to the left, and then translated 7 units upward, the resulting expression will be y = 2tan(x + 2) + 7

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