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you jump out of an airplane at 2000ft and fall 1000ft before opening your parachute (without any forces opposing ) what the speed at the time when you open the chute ? ( physics: potencial energy)​

Respuesta :

Answer:

Correct answer: V = 78.07 m/s

Explanation:

We can solve this problem combined with the help of kinetics or with energy conservation laws.

The first way is:

This is a free fall with no initial speed (velocity)

The formula for this case is:  V² = 2 g h , we will take that g = 10 m/s²

We must first convert the ft into meters

The relationship is 1 ft = 0.3048 m, according to this 1,000 ft = 304.8 m which is also the height of the fall   h = 304.8 m

V² = 2 · 10 · 304.8 = 6,096 => V = √6,096 = 78.07 m/s

V = 78.07 m/s

Otherwise it cannot be solved because we do not have a mass of parachute jumper.

God is with you!!!