Option A:
The probability that Everett and Finley end up with an even number and a blue disk is [tex]\frac{1}{6}[/tex].
Solution:
Given data:
Everett is rolling a block with numbers = {1, 2, 3, 4, 5, 6}
Finley is drawing one disk from basket with colors = {blue, red, yellow}
Total number of numbers = 6
Total number of colors = 3
[tex]$\text { Probability }=\frac{\text {Number of possible outcomes}}{\text {Total number of outcomes}}[/tex]
[tex]$P\text{(Even number)} =\frac{3}{6}$[/tex]
[tex]$P\text{(Blue disk)} =\frac{1}{3}$[/tex]
[tex]$P\text{(Even number and Blue disk)} =\frac{3}{6}\times\frac{1}{3}$[/tex]
[tex]$=\frac{3}{18}[/tex]
Divide numerator and denominator by the common factor 3.
[tex]$=\frac{3\div3}{18\div3}[/tex]
[tex]$=\frac{1}{6}[/tex]
Option A is the correct answer.
Hence the probability that Everett and Finley end up with an even number and a blue disk is [tex]\frac{1}{6}[/tex].
