Answer:
[tex]\large\boxed{\large\boxed{\text{Option B. }3/10}}[/tex]
Explanation:
I will rewrite the table for better understanding:
Table
OUTCOMES
0 1 3 5
0 0,0 0,1 0,3 0,5
2 2,0 2,1 2,3 2,5
4 4,0 4,1 4,3 4,5
6 6,0 6,1 6,3 6,5
8 8,0 8,1 8,3 8,5
What is the probability of getting a number greater than 2 in the first game and a number greater than 1 in the second game?
The probability of an event is calculated as the quotient of the number of favorable outcomes and the number of total possible outcomes.
[tex]Probability(event)=\frac{\text{number of favorable outcomes}}{\text{total number of possible outcomes}}[/tex]
i) Favorable outcomes:
The total number of favorable outcomes is the combination of outcomes with a 4, 6, or 8 in the first number (representing getting a number greater than 2 in the first game) and a 3 or 5 in the second number (representing getting a number greater than 1 in the second game).
Those are: (4,3); (4,5); (6,3); (6,5); (8,3); and (8,5).
Which is a total of 6 favorable outcomes.
ii) Possible outcomes:
That is the total sample space, i.e. 4 × 5 = 20 outcomes.
iii) Compute the probability:
[tex]Probability=6/20=3/10[/tex]
