Answer:
Step-by-step explanation:
Perimiter = distance around. In this case the sum of the lengths and breadths of the dog run.
let a = length and b = breadth
2a + 2b ≥ 48
2a + 2b ≤ 80
since a = 20, we substitute for a in both equations
2 (20) + 2b ≥ 48
40 + 2b ≥ 48
2b ≥ 48 - 40
2b ≥ 8
b ≥ 4
In the second equation, we have;
2(20) + 2b ≤ 80
40 +2b ≤ 80
2b ≤ 80 - 40
2b ≤ 40
b ≤ 20
So the width must be between 4ft and 20ft for the dog run to be within the requisite criteria