09-02-2020
Mathematics

contestada

-2i(3-9i) as a complex number in standard form (a+bi)

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Hrishii Hrishii

09-02-2020

Step-by-step explanation:

[tex] - 2i(3 - 9i) \\ \\ = - 2i \times 3 + 2i \times \: 9i \\ \\ = - 6i + 18 {i}^{2} \\ \\ = - 6i + 18( - 1) \\ \\ = - 6i - 18 \\ \\ = - 18 - 6i \\ \\ = - (18 + 6i) \implies \: a + bi[/tex]

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