The diagonal of a rectangle measures 65 centimeters. The length of the rectangle is 33 cen-
timeters. Consider the measurements to be exact.
Find the width of the rectangle.
Find the area of the rectangle.

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Answer:

[tex]\large \boxed{\text{56 cm; 1848 cm}^{2}}[/tex]

Step-by-step explanation:

The diagonal divides the rectangle into two right triangles.

A. Calculate the width of the rectangle

We can use Pythagoras' Theorem.

[tex]\begin{array}{rcl}a^{2} + b^{2} & = & c^{2}\\a^{2} + 33^{2} & = & 65^{2}\\a^{2} +1089 & = & 4225\\a^{2} & = & 3136\\a & = & \mathbf{56}\\\end{array}\\\text{The width of the triangle is $\large \boxed{\textbf{56 cm}}$}[/tex]

B. Calculate the area of the rectangle

The formula for the area A of a rectangle is

A = lw  = 33 cm × 56 cm = 1848 cm²

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