Respuesta :
Answer:
The ships are 66 meters apart.
Step-by-step explanation:
For the sake of convenience, let us label ships A and B
As shown in the figure, the distances to the ships from right triangles.
The distance to the ship A is [tex]d_1[/tex] and it is given by
[tex]tan (61^o)= \dfrac{50}{d_1}[/tex]
[tex]d_1=\dfrac{50}{tan (61^o)}[/tex]
[tex]\boxed{d_1= 27.71m}[/tex]
And the distance to the ship B is [tex]d_2[/tex] and is given by
[tex]tan (28^o)= \dfrac{50}{d_2}[/tex]
[tex]d_2=\dfrac{50}{tan (28^o)}[/tex]
[tex]\boxed{ d_2=94.04m}[/tex]
Therefore, the distance [tex]d[/tex] between the ships A and B is
[tex]d= d_2-d_1=94.04-27.7\\\\\boxed{d=66m}[/tex]
In other words, the ships are 66 meters apart.

Answer:
66.32 meters
Step-by-step explanation:
see the attached figure to better understand the problem
step 1
In the right triangle ABC
Find the measure of side BC
[tex]tan(62^o)=\frac{50}{BC}[/tex] ---> TOA (opposite side divided by the adjacent side)
[tex]BC=\frac{50}{tan(61^o)}=27.72\ m[/tex]
step 2
In the right triangle ABD
Find the measure of side BD
[tex]tan(28^o)=\frac{50}{BD}[/tex] ---> TOA (opposite side divided by the adjacent side)
[tex]BD=\frac{50}{tan(28^o)}=94.04\ m[/tex]
step 3
How far apart are the ships?
[tex]CD=BD-BC[/tex]
substitute
[tex]CD=94.04-27.72=66.32\ m[/tex]
