Respuesta :

Kinetic Energy (Translational, in all directions) of a gas as per Kinetic theory of gases at abs. Temperature T:

         per molecule:  KE = 3/2 * k_B T

            per mole:      KE = 3/2 * R * T

           k_B = Boltzmann's constant. R= Universal gas constant.

 Kinetic Energy of a gas (as per mechanics)

                   KE = 1/2 m (Vrms)²

              or  KE = 1/2 M (Vrms)²

      m = mass of a molecule, M = Molar mass of the gas.

Hence,  (Vrms)² = 3 k_B T /m = 3 R T /M

R = 8.3 J/°°K/mole 

M = 44 gm/mole  for CO2  = 0.044 kg/mole

   (Vrms)² = 3 * 8.314 J/°K/mole * (273+27)° / (0.044 kg/mole)

       Vrms = 412.38 m/sec

Answer: not Possible

Explanation:

27 is not. square number