a person was using a spanner to loosen a tight nut.Their mass was 50kg the spanner was 0.5m long i) what is the persons weight? ii) what is the maximum turning force they would achieve by standing on the spanner show your working.

Respuesta :

1) Weight of the person: 490 N

2) Maximum torque: 245 Nm

Explanation:

1)

The weight of a body is equal to the gravitational force exerted on the body; it is given by the equation

[tex]F=mg[/tex]

where

m is the mass of the body

g is the acceleration due to gravity

For the person in this problem,

m = 50 kg is the mass

[tex]g=9.8 m/s^2[/tex] is the acceleration due to gravity on Earth's surface

Therefore, the weight of the person is

[tex]F=(50)(9.8)=490 N[/tex]

2)

The turning force (also called torque) exerted by a force rotating an object is given by

[tex]\tau = Fd sin \theta[/tex]

where

F is the magnitude of the force

d is the length of the arm (the distance between the force and the pivotal point)

[tex]\theta[/tex] is the angle between the direction of the force and the arm

For the spanner in this problem,

F = 490 N is the force applied (the weight of the person)

d = 0.5 m is the arm (the length of the spanner)

The maximum torque is obtained when [tex]\theta=90^{\circ}[/tex], therefore it is:

[tex]\tau=(490)(0.5)(sin 90^{\circ})=245 N\cdot m[/tex]

Learn more about weight:

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About torque:

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