Answer: [tex]6 + 2 (x+4)[/tex] = [tex]\frac{3}{2}[/tex][tex](3-x)[/tex]
Step-by-step explanation:
let the number be x , then :
six added to twice the sum of a number and four means :
[tex]6 + 2 (x+4)[/tex]
one half of the difference of three and the number means :
[tex]\frac{3}{2}[/tex][tex](3-x)[/tex]
combining the two , we have
[tex]6 + 2 (x+4)[/tex] = [tex]\frac{3}{2}[/tex][tex](3-x)[/tex]
