The total work done on the box will be equal to 1100 J.
Answer:
Option A
Explanation:
As per work energy theorem, total work done on any object will be equal to the change in kinetic energy of the object.
So change in kinetic energy = [tex]\frac{1}{2}*m*(v^{2}-u^{2})[/tex]
Here, m is the mass, v is the final velocity and u is the initial velocity of the object.
As the mass is given as 11 kg and the final velocity is given as 15 m/s with the initial velocity of the box being 5.1 m/s, then the change in kinetic energy will be as follows.
Kinetic energy = (0.5×11)×([tex](15)^{2} -(5.1)^{2}[/tex])=0.5×11×198.99
Thus, the kinetic energy = 1094 J.
According to the options, this value is nearly equal to 1100 J. Thus, the total work done on the box will be equal to 1100 J.