Find tan0 where 0 is the angle shown. Give an exact value, not a decimal approximation.

Answer:
[tex]\frac{3}{\sqrt{55} }[/tex]
Step-by-step explanation:
We require to find the third side of the triangle.
Using Pythagoras' identity.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.
let x represent the third side, then
x² + 3² = 8², that is
x² + 9 = 64 ( subtract 9 from both sides )
x² = 55 ( take the square root of both sides )
x = [tex]\sqrt{55}[/tex]
Thus
tanΘ = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{3}{\sqrt{55} }[/tex]
Answer:
tan(θ) = (3√55)/55
Step-by-step explanation:
The third side (a) of the triangle is found from the Pythagorean theorem as ...
a^2 + b^2 = c^2
a^2 + 3^2 = 8^2
a^2 = 64 - 9 = 55
a = √55
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The mnemonic SOH CAH TOA reminds you that the tangent relation is ...
Tan = Opposite / Adjacent
Here, the side opposite angle θ has length 3, and the side adjacent is the one we just found, √55. Then ...
tan(θ) = 3/√55
Rationalizing the denominator by multiplying by (√55)/(√55), we find the tangent to be ...
tan(θ) = (3/55)√55