Answer:
[tex]a_n=\frac{83}{100}*a_{n-1},where\:a_1=12[/tex]
Step-by-step explanation:
If the first term of the sequence is 12, then [tex]a_1=12[/tex]
Since the sequence by 17% each term, there is a common ratio of [tex]r=1-0.17\\\implies r=\frac{83}{100}[/tex]
Therefore the sequence is a geometric sequence.
The recursive formula is given as:
[tex]a_n=a_{n-1}*r[/tex]
We substitute the common ratio to obtain:
[tex]a_n=\frac{83}{100}*a_{n-1},where\:a_1=12[/tex]
