A rectangle is formed from a square by adding 6 m to one side and 3 m to the other side. The area of the rectangle is 238 m². Find the dimensions of the original square.

Respuesta :

Answer:

Therefore,

Dimensions of the Original Square is

[tex]x =11\ m[/tex]

Step-by-step explanation:

Given:

Let the side of Square be "x" meter

Then the Dimensions of a Rectangle is formed by adding 6 m to one side and 3 m to the other side wil be.

[tex]Length = x+6\\\\Width=x+3[/tex]

Area of Rectangle =238 m²

To Find:

x = ?  (Dimension of Original Square)

Solution:

Area of Rectangle is given by

[tex]\textrm{Area of Rectangle}=Length\times Width[/tex]

Substituting the values we get

[tex]238=(x+6)\times (x+3)[/tex]

Opening the Parenthesis we get

[tex]238=x^{2}+9x+18\\\\x^{2}+9x+-220=0[/tex]    ......Which is Quadratic equation

On Factorizing and Splitting the middle term we get

[tex]x^{2}+20x-11x-220=0\\\\x(x+20)-11(x+20)=0\\\\(x+20)(x-11)=0\\\\x+20=0\ or\ x-11=0\\\\x=-20\ or\ x=11[/tex]

As distance cannot be negative therefore,

[tex]x =11[/tex]

Therefore,

Dimensions of the Original Square is

[tex]x =11\ m[/tex]

Answer:

11 meter

Step-by-step explanation:

Given: A rectangle is formed from a square by adding 6 m to one side and 3 m to the other side.

The area of the rectangle is 238 m².

Now, finding the dimension of the original square.

Lets assume the side of square be "s".

∴ Width= [tex]s+6[/tex]

Length= [tex]s+3[/tex]

We know, area of rectangle= [tex]width\times length[/tex]

Subtituting the value in the formula to find the dimension or side of square.

using distributive property of multiplication.

⇒[tex]238= s^{2} + 3s+6s+18[/tex]

Subtracting both side by 238

⇒ [tex]s^{2} + 9s-220= 0[/tex]

Solving by using quadratic formula to find value of s.

Formula: [tex]\frac{-b\pm \sqrt{b^{2}-4(ac) } }{2a}[/tex]

∴ In the expression [tex]s^{2} +9s-220[/tex], we have a= 1, b= 9 and c= -220.

Now, subtituting the value in the formula.

= [tex]\frac{-9\pm \sqrt{9^{2}-4(1\times-220) } }{2\times1}[/tex]

= [tex]\frac{-9\pm \sqrt{81-4(-220) } }{2}[/tex]

= [tex]\frac{-9\pm \sqrt{81+880 } }{2}[/tex]

= [tex]\frac{-9\pm 31 }{2}[/tex]

= [tex]\frac{-40}{2} or\ \frac{22}{2}[/tex]

= -20 or 11

Ignoring negative result as dimension cannot be negative.

∴ The dimension of square will be 11 meter.