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Ashley is covering the front of her house with wood panels. Her house is 10 feet tall and 12 feet wide. She does not want to cover her 8 foot tall front door. If Ashley uses 88 square feet of wood panels to cover the front of her house, how wide is her front door?

Respuesta :

Answer:

The width of the door is 4 feet.

Step-by-step explanation:

Given,

For house,

Length = 10 ft

Width = 12 ft

Length of door = 8 ft

Quantity of wood used to cover the front of house = 88 sq. ft

we have to find the width of the door.

Solution,

Since the front of the house is in rectangular shape.

So we use the formula of area of rectangle, i.e. length times width.

Area of the front of the house = [tex]10\times12=120\ ft^2[/tex]

Let the width of the door be 'w'.

So, area = [tex]8\times w=8w[/tex]

Now according to question,

Ashley does not want to cover her 8 foot tall front door.

So we can say that;

The quantity of wood used to cover the front of the house is equal to area of the front of the house minus area of the door.

Now we substitute the given values;

[tex]88=120-8w[/tex]

combining the like terms, we get;

[tex]8w=120-88\\\\8w=32[/tex]

Now dividing both side by '8' using division property, we get;

[tex]\frac{8w}{8}=\frac{32}{8}\\\\w=4\ ft[/tex]

Hence The width of the door is 4 feet.

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