Need help with this and need to show all work.

Answer:
The answer to your question is 6.- x = 13 7.- Perimeter = 49
Step-by-step explanation:
6.- If the triangles are similar then their angles measure the same
8x + 16 = 120
8x = 120 - 16
8x = 104
x = 104/8
x = 13
7.- Use proportions to find the length of the other sides
[tex]\frac{AC}{AD} = \frac{XZ}{XY}[/tex] [tex]\frac{AC}{11} = \frac{32}{22}[/tex] AC = 11[tex]\frac{32}{22}[/tex]
AC = 16
[tex]\frac{BC}{11} = \frac{44}{22}[/tex] BC = [tex]11 \frac{44}{22}[/tex]
BC = 22
Find the perimeter
Perimeter = AB + BC + AC
= 11 + 22 + 16
= 49
Answer:
Step-by-step explanation:
6) ∆ ABC is similar to ∆ CDE. This means that
Angle B = angle D
Therefore,
8x + 16 = 120
Subtracting 16 from the left hand side and the right hand side of the equation, it becomes
8x + 16 - 16 = 120 - 16
8x = 104
Dividing the left hand side and the right hand side of the equation by 8, it becomes
8x/8 = 104/8
x = 13
7) ∆ ABC is similar to ∆ XYZ. It means that
AB/XY = BC/YZ = AC/XZ
Therefore
11/22 = AC/32
22AC = 32 × 11 = 352
AC = 352/22 = 16
The factor is 2
Therefore,
BC = 44/2 = 22
Perimeter of ∆ABC = 22 + 16 + 11 = 49