Respuesta :
Answer:
Area of rectangle is [tex]w^2+5w[/tex]
Perimeter of Rectangle is [tex]4w+20[/tex].
Step-by-step explanation:
Given:
Let the width of the rectangle be 'w'.
Also Given:
A rectangle has a length that is 5 meters greater than the width.
Length of rectangle = [tex]w+5\ meters[/tex]
We need to write expression for Area of rectangle and Perimeter of rectangle.
Solution:
Now we know that;
Perimeter of rectangle is equal to twice the sum of the length and width.
framing in equation form we get;
Perimeter of rectangle = [tex]2(w+5+w)=2(2w+5) =4w+20[/tex]
Also We know that;
Area of rectangle is length times width.
framing in equation form we get;
Area of rectangle= [tex]w(w+5) = w^2+5w[/tex]
Hence Area of rectangle is [tex]w^2+5w[/tex] and Perimeter of Rectangle is [tex]4w+20[/tex].
