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This circle is centered at the point (3, 2), and the length of its radius is 5. What
is the equation of the circle?
O A. (x-2)2 + (y- 3)2 = 25
O B. (x-3)2 + (x - 2)2 = 25
O c. (x2-3) + (2-2) = 52
OD. (x+3)2 + (y + 2)2 = 5

Respuesta :

Answer:

There is no  corrrect option given but the correct answer is below may help you.

Therefore,

Equation of Circle is

[te](x-3)^{2}+(y-2)^{2}=25[/tex]

Step-by-step explanation:

Given:

Let center be C,

[tex]C(h,k)=(3,2)[/tex]

[tex]Radius = r = 5[/tex]

To Find:

Equation of Circle = ?

Solution:

The Equation of Circle with center (h , k) and radius r is given as

[tex](x-h)^{2}+(y-k)^{2}=r^{2}[/tex]

Substituting the values we get

[tex](x-3)^{2}+(y-2)^{2}=5^{2}\\\\(x-3)^{2}+(y-2)^{2}=25[/tex]

Therefore,

Equation of Circle is

[te](x-3)^{2}+(y-2)^{2}=25[/tex]

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