Answer:
Julio travel 3 hours by biking and 4 hours by walking.
Step-by-step explanation:
Given:
Julio started biking to the park traveling 8 mph, after some time the bike got a flat so Julio walked the rest of the way, traveling 7 mph.
If the total trip to the park took 7 hours and it was 52 miles away.
Now, to find the time Julio travel at each speed.
The speed travelled by the bike = 8 mph.
The speed travelled by the walking = 7 mph.
Let the time Julio travel with bike be [tex]x.[/tex]
And the time Julio travel by walking be [tex]y.[/tex]
As, given Julio started biking to the park traveling, after some time the bike got a flat so Julio walked the rest of the way,
Thus, the total time taken:
[tex]x+y=7[/tex]
[tex]y=7-x\ \ \ .......(1)[/tex]
So, the distance travelled by bike:
Speed × time
[tex]8\times x=8x[/tex]
And, the distance travelled by walking:
Speed × time
[tex]7\times y=7y[/tex]
Now, the total distance travelled by Julio:
[tex]8x+7y=52[/tex]
Substituting the value of [tex]x[/tex] from equation (1) we get:
[tex]8x+7(7-x)=52[/tex]
[tex]8x+49-7x=52\\\\x+49=52[/tex]
Subtracting both sides by 49 we get:
[tex]x=3.[/tex]
The time Julio travelled with bike = 3 hours.
Now, to get the time Julio travelled by walking by substituting the value of [tex]x[/tex]:
[tex]y=7-x\\\\y=7-3\\\\y=4\ hours.[/tex]
The time Julio travelled by walking = 4 hours.
Therefore, Julio travel 3 hours by biking and 4 hours by walking.